Question

$( \frac{1}{6} x + 2y) {}^{3}$
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Answer 1

${( \frac{1}{6} x + 2y) }^{3} = \frac{1}{216} {x}^{3} + \frac{1}{6} {x}^{2} y + 2x {y}^{2} + 8 {y}^{3}$