Question

Решите уравнение 32/30+x+56/30-x=3

Answer 1

Ответ:

$x_{1} =-10\\x_{2} =2$

Объяснение:

$\frac{32}{30+x} +\frac{56}{30-x} =3$

32*(30*х)+56*(30+х)=3*(30+х)*(30-х)

960-32х+1680+56х=2700-90х+90х-3$x^{2}$

$3x^{2} +24x-60=0$

$x^{2} +8x-20=0$

$x_{1} +x_{2} =-8\\x_{1} *x_{2} =-20$

$x_{1} =-10\\x_{2} =2$