Question

Найди корни уравнения 13,3(x−7,6)(x−28)=0.

Answer 1

Ответ:

$\frac{133}{10} * (x -\frac{38}{5} ) * (x-28) = 0\\\\(x-\frac{38}{5} * (x - 28) = 0\\\\x - \frac{38}{5} = 0\\x -28 = 0 \\\\x_{1} = \frac{38}{5} \\x_{2} = 28$