Question

помогите решить задание 137​

Answer 1

1)x^2+6x+9
2)y^2-8y+16
3)4m^2-20m+25
4)49a^2+84ab+36b^2
5)0,04x^2-4xy+100y^2


^2-это значит в квадрате

Answer 2

$1) {(x + 3)}^{2} = x {}^{2} +6x+9.$

$2) {(4 - y)}^{2} = 16 - 8y + {y}^{2} .$

$3) {(2m - 5)}^{2} = 4 {m}^{2} - 20m + 25.$

$4) {(7a + 6b)}^{2} = 49 {a}^{2} + 84ab + 36 {b}^{2} .$

$5) {(0.2x - 10y)}^{2} =0.04 {x}^{2} - 4xy + 100 {y}^{2} .$