Question

Помогите пожалуйста.

Answer 1

$1)\; \; \sqrt{0,18}\; \vee \; 0,9\; \; ,\; \; \; 0,9=\sqrt{0,9^2}=\sqrt{0,81}\\\\0,18<0,81\; \; \to\; \; \sqrt{0,18}<\sqrt{0,81}\; \; \to \; \; \underline {\sqrt{0,18}<0,9}\\\\\\2)\; \; \frac{6}{13}\; \vee \; \sqrt{0,34}\; \; \; ,\; \; \; \frac{6}{13}=\sqrt{\frac{36}{169}}\approx\sqrt{0,21}\\\\0,21<0,34\; \; \to \; \; \; \sqrt{0,21}<\sqrt{0,34}\; \; \to \; \; \underline {\frac{6}{13}<\sqrt{0,34}}$

$3)\; \; \sqrt{7\frac{1}{9}}\; \vee \; 2,45\\\\\sqrt{7\frac{1}{9}}=\sqrt{\frac{64}{9}}=\frac{8}{3}=2\frac{2}{3}\; \; ,\; \; 2,45=2\frac{45}{100}=2\frac{9}{20}\\\\2\frac{2}{3}>2\frac{9}{20}\; \; \to \; \; \underline {\sqrt{7\frac{1}{9}}>2,45}$

$4)\; \; 5,7\; \vee \; \sqrt{27,05}\\\\5,7=\sqrt{5,7^2}=\sqrt{32,49}\\\\32,49>27,05\; \; \to \; \; \sqrt{32,49}>\sqrt{27,05}\; \; \to \; \; \underline {5,7>\sqrt{27,05}}$