Question

срочнооо дайте отвте!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

$\frac{(3abc^{2})^{2}(2ac)^{2}*b}{-6a^{3}b^{2}c^{5}}= \frac{3^{2}*a^{2}*b^{2}*c^{4}*2^{2}*a^{2}*c^{2}*b}{-6a^{3}b^{2}c^{5}}=\frac{36a^{4}b^{3}c^{6}}{-6a^{3}b^{2}c^{5}}=-6abc$