Question

Даю 50 баллов! Срочно!

Answer 1

$A1.\; \; \frac{2}{3-x}\\\\A2.\; \; a=-0,7\; ,\; \; b=-0,3:\; \; \frac{a+b}{a-b}=\frac{-0,7-0,3}{-0,7+0,3}=\frac{-1}{-0,4}=\frac{10}{4}=2,5\\\\A3.\; \; \; \frac{5a\, (a-1)}{13a+2}\; \; \; \to \; \; \; 13a+2\ne 0\; \; ,\; \; a\ne -\frac{2}{13}\\\\A4.\; \; \; \frac{24\, a^5\, b^8}{(-2a^3b^3)^2}=\frac{24\, a^5\, b^8}{4\, a^6\, b^6}=\frac{6\, b^2}{a}$