Question

6cos60-2ctg45°*sin45°
* - умножить
° - градусы​

Answer 1

Ответ:

$6cos60^{\circ} - 2ctg45^{\circ} \cdot sin45^{\circ} = 3 - \sqrt{2}$

Объяснение:

$cos60^{\circ} = \frac{1}{2}$

$ctg45^{\circ} = 1$

$sin45^{\circ} = \frac{\sqrt{2}}{2}$

$6cos60^{\circ} = 3$

$2ctg45^{\circ} \cdot sin45^{\circ} = 2 \cdot\frac{\sqrt{2}}{2} = \sqrt{2}$