Question

помогите пожалуйста с и) к) л) м) (дам 100 балов)

Answer 1

и)

$\frac{1}{2}(x-4) + 3x = 5\\\\x-4 + 6x = 10\\\\x+6x = 10+4\\\\7x = 14\\\\ x =2$

к)

$2(x+\frac{3}{5}) - x = 3\frac{1}{5}\\\\2x + 1\frac{1}{5} - x = 3\frac{1}{5}\\\\2x - x = 3\frac{1}{5}-1\frac{1}{5}\\\\x = 2$

л)

$5x - (\frac{1}{2}x + 9) = 18\\\\5x - \frac{1}{2}x - 9 = 18\\\\5x - \frac{1}{2}x = 18 +9\\\\4\frac{1}{2}x = 27\\\\x = 6$

м)

$-2(\frac{1}{3}x + 7) = -21\\\\-\frac{2}{3}x - 14 = -21\\\\-\frac{2}{3}x = -21+14\\\\-\frac{2}{3}x = -7\\\\\frac{2}{3}x = 7\\\\x = \frac{7*3}{2} = \frac{21}{2}\\\\x = 10\frac{1}{2}$