Question

Хелп плиз, фенк ю❤❤❤❤❤​

Answer 1

$x^{2} -2x-1=0\\D= 4+4 = 8\\x1;2= \frac{2+-\sqrt{8} }{2}= 1+-\sqrt{2}\\ \\\\4x^{2} -12x+9=0\\(2x-3)^{2} =0\\x=1,5$