Question

$y = \sqrt{3 - 4x}$
$2y = \sqrt{2 + x} + \sqrt{3 - x}$
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Answer 1

$1)\; \; y=\sqrt{3-4x}\\\\ODZ:\; \; 3-4x\geq 0\; \; \to \; \; \; 4x\leq 3\; ,\; \; x\leq 0,75\\\\x\in D(y)=(-\infty \, ;\; 0,75\, ]\\\\\\2)\; \; y=\sqrt{2+x}+\sqrt{3-x}\\\\ODZ:\; \; \left \{ {{2+x\geq 0} \atop {3-x\geq 0}} \right.\; \; \left \{ {{x\geq -2} \atop {x\leq 3}} \right.\; \; \Rightarrow \; \; \; x\in [-2\, ;\, 3\; ]\\\\D(y)=[-2\, ;\, 3\; ]$

Answer 2

Ответ: во вложении Объяснение: