Question

геометрическая прогрессия помогите пжлст​

Answer 1

$b_{1} = \dfrac{16}{27}; \ b_{2} = \dfrac{16}{9}$

$q = \dfrac{b_{2}}{b_{1}} = \dfrac{\dfrac{16}{9} }{\dfrac{16}{27} } = 3$

$b_{8} = b_{1}q^{7} = \dfrac{16}{27} \cdot 3^{7} = 16 \cdot 3^{-3} \cdot 3^{7} = 16 \cdot 3^{4} = 16 \cdot 81 =1296$

Ответ: 1296.