Question

1/3х-4/9>х(х-1)
Помгите​

Answer 1

$\frac{1}{3} x-\frac{4}{9} >x^{2} -x\\\frac{1}{3} x-\frac{4}{9} -x^{2} +x>0\\\frac{4}{3}x-\frac{4}{9} -x^{2} +x>0\\12x-4-9x^{2} >0\\-(9x^{2} -12x+4)>0\\-(3x-2)^{2} >0\\(3x-2)^{2} <0$

$x$∈∅

Answer 2

$\frac{1}{3} - \frac{4}{9} > x(x - 1)$

$\frac{1}{3} - \frac{4}{9} > 2x - 1$

$- \frac {1}{9} > 2x - 1$

$2x = \frac{10}{9}$

$x = - \frac{8}{9}$

удачи)