Question

(модеры не удаляйте мой вопрос пж)Решить дробь через НОК​

Answer 1

Ответ:

Пошаговое объяснение:

№ 304

а) 3 7/8 + 27 1/64

8= 2*2*2

64= 2*2*2*2*2*2

НОК ( 8;64) = 64

домножим 7/8 на 8

$3\frac{7}{8} + 27 \frac{1}{64} =(3+27)+(\frac{7*8}{8*8} +1/64)=30+ (\frac{56}{64}+\frac{1}{64})= 30 \frac{57}{64}$

b) $17 \frac{3}{10}+ 33\frac{5}{6}$

10= 2*5

6= 2*3

НОК (10;6)= 2*3*5=30

домножим $\frac{3}{10}$ на 3 , а $\frac{5}{6}$ на 5

$17 \frac{3}{10} + 33 \frac{5}{6}= (17+33)+ ( \frac{3*3}{10*3} +\frac{5*5}{6*5}= 50 +(\frac{9}{30} + \frac{25}{30} )= 50 \frac{34}{30}= 51 \frac{4}{30}= 51 \frac{2}{15}$

с) $43\frac{5}{12} - 21\frac{3}{20}$

12= 2*2*3

20= 2*2*5

НОК ( 12; 20) = 2*2*3*5= 60

домножим $\frac{5}{12}$ на 4 , а $\frac{3}{20}$ на 3

$43\frac{5}{12} - 21\frac{3}{20}= ( 43-21) + ( \frac{5*4}{12*4}- \frac{3*3}{20*3})= 22+(\frac{20}{60}- \frac{9}{60} )= 22 \frac{11}{60}$

d) $51- 38\frac{15}{17}$ =  $50\frac{17}{17}$ -  $38\frac{15}{17}$=  $12\frac{2}{17}$

e)  $6*15 \frac{17}{32}= 6* \frac{15*32+17}{32} =\frac{6*497}{32} =\frac{2982}{32}=93 \frac{6}{32}= 93\frac{3}{16}$

f) $54\frac{6}{19} : 18 = \frac{54*19+6}{19} * \frac{1}{18}= \frac{1043}{19} *\frac{1}{18} =\frac{1043}{342}= 3\frac{17}{342}$

№305

а) $13\frac{7}{12} + 42\frac{1}{6}$

12= 2*2*3

6=2*3

НОД(6;12)=2*2*3=12

домножим $\frac{1}{6}$ на 2

$13 \frac{7}{12} + 42\frac{1*2}{6*2}=(13+42)+(\frac{7}{12} +\frac{2}{12})= 55 \frac{9}{12}=55\frac{3}{4}$

b) $872\frac{5}{8} + 15\frac{25}{36}$

8=2*2*2

36=2*2*3*3

НОК ( 8;36) = 2*2*2*3*3=72

домножим $\frac{5}{8}$ на 9 , $\frac{25}{36}$ на 2

$872\frac{5}{8} + 15\frac{25}{36}= ( 872+15)+(\frac{5*9}{8*9}+\frac{25*2}{36*2})= 887 +(\frac{45}{72} +\frac{50}{72})= 887 \frac{95}{72}= 888 \frac{23}{72}$с) $473\frac{5}{12}- 362 \frac{4}{21}$

12= 3*4

21= 3*7

НОК ( 12;21) = 3*4*7= 84

домножим $\frac{5}{12}$ на 7 , а $\frac{4}{21}$ на 4

$473 \frac{5}{12}- 362 \frac{4}{21}= ( 473-362)+(\frac{5*7}{84} -\frac{4*4}{84}) = 111+ \frac{35-16}{84} = 111\frac{19}{84}$

d)  $55 - 23\frac{51}{64}= 54 \frac{64}{64} - 23\frac{51}{64}= ( 54-23) +( \frac{64}{64} -\frac{51}{64})= 31 \frac{13}{64}$

e)$11 * 4\frac{17}{31}= 11* \frac{4*31+17}{31} = 11* \frac{141}{31}=\frac{11*141}{31} =\frac{1551}{31}= 50 \frac{1}{31}$

f) $52 \frac{2}{3} : 13 = \frac{52*3+2}{3} *\frac{1}{13}= \frac{158}{3} *\frac{1}{13}=\frac{158}{39} =4\frac{2}{39}$