Question

$1) \sqrt{2x + 1} = 1 \\ 2) \sqrt{x + 2} = x$
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Answer 1

Ответ:

$x_1 = - 1 \\ x_2 = 2$

Объяснение:

$1) \sqrt{2x + 1} = 1 \\ 2x + 1 = 1 \\ 2x = 0 \\ x = 0 \\ \\ 2) \: \sqrt{x + 2} = \\ x + 2= {x}^{2} \\ x + 2 - {x}^{2} = 0 \\ - {x}^{2} + x + 2 = 0 \\ {x}^{2} - x - 2 = 0 \\ {x}^{2} + x - 2x - 2 =0 \\ x(x + 1) - 2(x + 1) = 0 \\ (x + 1)(x - 2) = 0 \\ x + 1 = 0 \\ x_1 = - 1 \\ x - 2 = 0 \\ x_2 = 2$