Question

$x ^{3} - 2x {}^{2} - 11x + 12 = 0$
помогите​

Answer 1

$x^3-2x^2-11x+12=0\\x^3-x^2-x^2+x-12x+12=0\\x^2(x-1)-x(x-1)-12(x-1)=0\\(x-1)(x^2-x-12)=0\\(x-1)(x^2-4x+3x-12)=0\\(x-1)(x(x-4)+3(x-4))=0\\(x-1)(x-4)(x+3)=0\\x_1=1; \ x_2=4; \ x_3=-3$

Ответ: 1; 4; -3