Question

разложите на множители : 0.216 -b^3 ​

Answer 1

$0.216 - {b}^{3} = \frac{27}{125} - {b}^{3} = \frac{1}{125} (27 - 125 {b}^{3} ) = \frac{1}{125} ( 3 - 5b)(9 + 15b + 25 {b}^{2} )$