Question

задача с логарифмами во вложениями :-)

Answer 1

a^log(a) b = b

lg = log(10)

10^lg 4 = 4

log(5) ( log(2) (log(6) 6^32)) = log(5) ( log(2) 32) =  log(5) ( log(2) 2^5 ) = log(5) 5 = 1

log(5) ( log(2) (log(6) 6^32)) + 10^lg 4 = 1 + 4 = 5

Answer 2

Ответ: во вложении Объяснение: