Question

$3x ^{2} - 11x + 6$
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Answer 1

Ответ:

Объяснение:

$3x^2 - 11x + 6 (a = 3, b = -11, c = 6)\\D = b^2 - 4ac = 121 - 4 * 3 * 6 = 49\\x_{1/2} = \frac{-b +/- \sqrt{D}}{2*a} = \frac{11 +/- 7}{6} = 3; \frac23;\\3x^2 - 11x + 6 = (x - \frac23)(x-3)$