Question

Помогите пжжж
Номер 810. 2)

Answer 1

$\frac{10-y}{6}+\frac{3y+8}{3}=\frac{y+6}{2}\; |\cdot 6\\\\10-y+2(3y+8)=3(y+6)\\\\10-y+6y+16=3y+18\\\\2y=-8\\\\y=-4$