Question

Алгебра, 9 класс, срочно
20+ баллов

Answer 1

$\frac{4}{x+1}-\frac{4}{1-x}=3\; \; ,\; \; \; ODZ:\; x\ne \pm 1\; ,\\\\\frac{4(1-x)-4(x+1)}{(x+1)(1-x)}=3\\\\\frac{4-4x-4x-4}{(x+1)(1-x)}=3\\\\\frac{-8x}{(x+1)(1-x)}=3\\\\-8x=3(x+1)(1-x)\\\\-8x=3(1-x^2)\\\\-8x=3-3x^2\\\\3x^2-8x-3=0\\\\D/4=4^2+3\cdot 3=25\; \; ,\; \; x_1=\frac{4-5}{3}=-\frac{1}{3}\; ,\; \; x_2=\frac{4+5}{3}=3\\\\Otvet:\; \; x=-\frac{1}{3}\; ,\; \; x=3\; .$