Question

помогите срочноо надо!​

Answer 1

Ответ:

a) 5x² + 10x = 0

x(5x + 10) = 0

x₁ = 0; x₂ = -2

б) 9x² - 4 = 0

(3x-2)(3x+2) = 0

x₁ = 2/3; x₂ = -2/3

в) x² - 7x + 6 =0

D = 49- 24 = 25

x₁ = 6; x₂ = 1

г) 2x² + 3x + 4 = 0

D = 9 - 32 = -23 < 0 - нет решений

д) (2x-1)²-9 = 0

((2x-1)-3)((2x-1)+3) = 0

2x-4 =0 или 2x + 2 =0

x₁ = 2; x₂ = -1

е) (3x+1)² = (x+2)²

(3x+1)² - (x+2)² = 0

((3x+1)-(x+2))((3x+1)+(x+2)) = 0

2x - 1 = 0 или 4x + 3 = 0

x₁ =0,5; x₂ = -0,75