Question

помогите пожалуйста

Answer 1

$12x^{2} -x+c=0\\\\x_{1}+x_{2}=\frac{1}{12}\\\\x_{1}=1\frac{1}{3}\\\\x_{2}=\frac{1}{12}-1\frac{1}{3}=\frac{1}{12}-\frac{4}{3}=\frac{1}{12}-\frac{16}{12}=-\frac{15}{12}=-\frac{5}{4}=-1\frac{1}{4}\\\\Otvet:\boxed{x_{2} =-1\frac{1}{4} }$