Question

ПОМОГИТЕ ПРОШУ❤❤❤
Al -> Al(3+)Cl3 -> Al(OH)3 ->(разложение)-> Al2O3 -> NaAlO2 -> Al2(SO4)3 -> Al(OH)3 -> AlCl3 -> NaAlO2

Answer 1

2Al+3Cl2=2AlCl3

AlCl3+3KOH=3KCl+Al(OH)3

2Al(OH)3=Al2O3+3H2O

Al2O3+2NaOH=(t°)=2NaAlO2+H2O

2NaAlO2+4H2SO4=Na2SO4+Al2(SO4)3+4H2O

Al2(SO4)3+6LiOH=3Li2SO4+2Al(OH)3

Al(OH)3+3HCl=AlCl3+3H2O

AlCl3+4NaOH=(t°)=NaAlO2+2H2O+3NaCl