Question

$- 18x^{2} \times \frac{2x - 1}{6} - 7x ^{2} \times \frac{2x + 1}{7}$
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Answer 1

Ответ:

$- 8 {x}^{3} + 2 {x}^{2}$

Объяснение:

$- 3 {x}^{2} \times( 2x - 1) - {x}^{2} \times (2x + 1) = - 6 {x}^{3} + 3 {x}^{2} - 2 {x}^{3} - {x}^{2} = - 8 {x}^{3} + 2 {x}^{2}$