Question

решите систему !!!!​

Answer 1

$\left \{ {{3^{x}-2^{2y}=77 } \atop {3^{0,5x}-2^{y}=7 }} \right.\\\left \{ {{(3^{0,5x}+2^{y})(3^{0,5x}-2^{y})=77} \atop {3^{0,5x}-2^{y}=7}} \right.\\ \left \{ {{7*(3^{0,5x}+2^{y})=77} \atop {3^{0,5x}-2^{y}=7}} \right.\\+\left \{ {{3^{0,5x}+2^{y}}=11 \atop {3^{0,5x}-2^{y}=7}} \right. \\2*3^{0,5x}=18=>3^{0,5x}=9\\3^{0,5x}=3^{2}=>0,5x=2=>x=4\\3^{0,5*4}-2^{y}=7=>2^{y}=3^{2}-7=9-7=2\\2^{y}=2=>y=1\\Otvet:x=4, y=1.$