Question

7x²+6x-1=0 как решить

Answer 1

$7x {}^{2} + 6x - 1 = 0 \\ 7x {}^{2} + 7x - x - 1 = 0 \\ 7x(x + 1) - (x + 1) = 0 \\ (x + 1)(7x - 1) = 0 \\ x + 1 = 0 \\ 7x - 1 = 0 \\ x = - 1 \\ x = \frac{1}{7}$

$x = - 1 \\ x = \frac{1}{7}$

Ответ: х= -1 х=1/7