Question

1) (a+1/7)²
2)(1/9+b)²
3)(n/4+m/3)²
4)(k/2-t/5)²
5)(4⅓-x)²
6)y+3¼)²
7)(z-5⅕)²
8)(4½+t)²​

Answer 1

$(a+\frac{1}{7})^{2}=a^{2}  +\frac{2}{7}a+\frac{1}{49} \\ \\ (\frac{1}{9} +b)^{2}=\frac{1}{81} +\frac{2}{9}b+b^{2} \\  \\ (\frac{n}{4}+\frac{m}{3})^{2}= \frac{n^{2} }{16}+\frac{1}{6}mn+\frac{m^{2} }{9} \\ \\ (\frac{k}{2}-\frac{t}{5})^{2}=\frac{k^{2} }{4}-\frac{1}5}kt+\frac{t^{2} }{25} \\ \\ (4\frac{1}{3}-x)^{2}=(\frac{13}{3} -x)^{2}=\frac{169}{9} -8\frac{2}{3}x+x^{2}=18\frac{7}{9}-8\frac{2}{3}x+x^{2}\\ \\ (y+3\frac{1}{4} )^{2}=(y+\frac{13}{4})^{2}=y^{2} + 6\frac{1}{2} y+10\frac{9}{16}$$\\ \\ (z-5\frac{1}{5}) ^{2}=(z-\frac{26}{5} )^{2}=z^{2} -10\frac{2}{5}z+27\frac{1}{25}\\ \\ (4\frac{1}{2} +t)^{2}=20\frac{1}{4}+9t+t^{2}$