Предмет: Физика, автор: lfey

Камень массой 20г,выпущенный вверх из рогатки,резиновый жгут который был растянут на 20 см,поднялся на высоту 40м.Найдите жесткость жгута

Ответы

Автор ответа: Mиstеrиk

mgh=kx^2/2 k=2mgh/x^2=2*0,02*10*40/0,04=400Н/м

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