Question

5Xв квадрате -7X+2=0​

Answer 1

Ответ:

x1= 1; х2 = 2/5

Объяснение:

$5x^{2} -7x+2=0\\D = b^{2} -4ac\\D = 7^2-4*5*2 = 49- 40 = 9\\\sqrt{D}=\sqrt{9} = 3\\x1 = (-b+\sqrt{D} )/2a\\x1 = (7+3)/2*5 = 1\\x2 = (-b-\sqrt{D} )/2a\\\\x2 = (7-3)/10 =2/5$