Question

x^5 > 32

16x^4 > 1

решить неравенство методом интервалов​

Answer 1

$x^5>32<=>x>2\\16x^4>1<=>(2x^2-1)(2x^2+1)>0<=>2x^2-1>0<=>\\<=>x^2>\frac{1}{2} =>x<-\frac{1}{2};x>\frac{1}{2}$