Question

СРОЧНО!!5^log2/5x + x^logx по основанию 5<10

Answer 1

Решение во вложении:

Answer 2

$5^{log_{\frac{2}{5}}x}+x^{log_x(5)}<10\\\left\{\begin{matrix}x>0 & \\  x\neq 1& \end{matrix}\right.\\\\5^{log_{\frac{2}{5}}x}+5<10\Leftrightarrow 5^{log_{\frac{2}{5}}x}<5\Leftrightarrow \\\Leftrightarrow log_{\frac{2}{5}}x<1\Rightarrow x>\frac{2}{5}\\\\x\in \left ( \frac{2}{5};+\infty \right )\setminus \begin{Bmatrix}1\end{Bmatrix}$