Question

Помогите с 6 заданием пожалуйста

Answer 1

1) $20a^{3}*(5a)^2=20a^{3}*25a^2=500a^5$

$2)-0,4x^{5}*(2x^3)^4=-0,4x^{5}*2^4x^{3*4}=-0,4x^{5}*16x^{12}=-6,4x^{5+12}=-6,4x^{17}$

$3)(-c^3)^2*12c^{6}=c^6*12c^{6}=12c^{12}$

$4)(3x^{6}y^{3})^4*(-\frac{1}{81}xy^{2})=3^4x^{24}y^{12}*(-\frac{1}{81}xy^{2})=$

$=81x^{24}y^{12}*(-\frac{1}{81}xy^{2})=-\frac{81}{81}x^{24+1}y^{12+2}=-x^{25}y^{14}$

$5)(-\frac{2}{3}ab^5)^3*18a^5b=-\frac{8}{27}a^3b^{15}*18a^5b=$

$=-\frac{8*18}{27}a^{3+5}b^{15+1}=-\frac{16}{3}a^{8}b^{16}=-5\frac{1}{3}a^{8}b^{16}$