Question

найдите корни уравнения​

Answer 1

Ответ:

$\sqrt{3} + \tan(x) = 1 - \sqrt{3} \tan(x) \\ \tan(x) (1 - \sqrt{3} ) = 1 - \sqrt{3} \\ \tan(x ) = (1 - \sqrt{3} ) \div (1 + \sqrt{3} ) \\ \tan(x) = \sqrt{3} - 2$

x=arctan(√3-2)+Пn