Question

представьте в виде произведения двухчлен:3)400-m^2 4)t^2-225​

Answer 1

$2)16-k^{2}=4^{2}-k^{2}=(4-k)(4+k)\\\\3)400-m^{2}=20^{2}-m^{2}=(20-m)(20+m)\\\\4)t^{2}-225=t^{2}-15^{2}=(t-15)(t+15)\\\\6)y^{2} -\frac{16}{81}=y^{2}-(\frac{4}{9})^{2}=(y-\frac{4}{9})(y+\frac{4}{9})\\\\8)\frac{25}{36}-64y^{2} =(\frac{5}{6})^{2}-(8y)^{2}=(\frac{5}{6} -8y)(\frac{5}{6}+8y)$

Answer 2

Ответ:  3)400-m^2 =(20-m)*(20+m)

4) t^2-225​=(t-15)*(t+15)

2) (4-k)*(4+k)

6) (y-4/9)*(y+4/9)

8) (5/6-8*y)*(5/6+8*y).

Объяснение: