Question

помогите пожалуйста по математике​

Answer 1

Ответ:

1) x = - 9

2) z = 1

3) y = 1

4) x = $\frac{16}{7}$

5) a = $\frac{8}{3}$

6) y = $\frac{8}{7}$

Пошаговое объяснение:

1) 2x + 3 = x - 6

2x - x = - 6 - 3

x = - 9

2) z + 4 - 3 = 2z

z - 2z = 3 - 4

- z = - 1

z = 1

3) 5 - 3y = 4 - 2y

- 3y + 2y = 4 - 5

- y = - 1

y = 1

4) 7 - 3x = 4x - 9

- 3x - 4x = - 9 - 7

- 7x = -16

x = $\frac{16}{7}$

5) 6a - 1 = 3a + 7

6a - 3a = 7 + 1

3a = 8

a = $\frac{8}{3}$

6) 10y - 3 = 5 + 3y

10y - 3y = 5 + 3

7y = 8

y = $\frac{8}{7}$