Question

помогите пожалуйста на кону зачет ​

Answer 1

1

$\displaystyle (1\frac{61}{64})^{-\frac{2}{3}}+198^0=(\frac{125}{64})^{-\frac{2}{3}}+1=(\frac{64}{125})^\frac{2}{3}+1=(\frac{4}{5})^2+1=0.64+1=1.64$

2

$\displaystyle \sf ((\frac{a-b}{a+b})^{-\frac{2}{3}})^{\frac{3}{4}}=(\frac{a+b}{a-b})^{\frac{2}{3}\cdot \frac{3}{4}}=(\frac{a+b}{a-b})^\frac{1}{2}=\sqrt{\frac{a+b}{a-b}}$