Question

Розвязать систему уравнений

Answer 1

Ответ:

Пошаговое объяснение:

$\displaystyle\\\left \{ {{3^{x-2y}=\dfrac{1}{3} } \atop {3^x+3^{2y}=4\sqrt{3} }} \right.\ \ \ \left \{ {{3^{x-2y}=3^{-1}} \atop {3^x+3^{2y}=4\sqrt{3} }} \right.\ \ \ \left \{ {{x-2y=-1} \atop {3^x+3^{2y}=4\sqrt{3} }} \right.\\\\\\\\\\  \left \{ {{x=2y-1} \atop {3^{2y-1}+3^{2y}=4\sqrt{3} }} \right.\ \ \ \ \left \{ {{x=2y-1} \atop {4\cdot3^{2y}=4\cdot3\sqrt{3} }} \right.\ \ \left \{ {{x=2y-1} \atop {3^{2y}=3^{1.5} }} \right.$

$\displaystyle\\\left \{ {{x=2y-1} \atop {2y=1.5}} \right.\ \ \ \ \left \{ {{x=2y-1} \atop {y=0.75}} \right. \ \ \ \ \left \{ {{x=0.5} \atop {y=0.75}} \right.$