Question

Решите пожалуйста, срочно

Answer 1

x³ - y³ = x² + xy + y²

x³ + y³ = x² - xy + y²

x³ - y³ = (x - y)(x² + xy + y²)

x³ + y³ = (x + y)(x² - xy + y²)

(x - y)(x² + xy + y²) - (x² + xy + y²) = 0

(x + y)(x² - xy + y²) - (x² - xy + y²) = 0

(x - y - 1)(x² + xy + y²) = 0

(x + y - 1)(x² - xy + y²) = 0

x = 0  y = 0

x - y = 1

x + y = 1

2x = 2

x = 1

y = 0

ответ (0, 0) (1, 0)