Предмет: Математика, автор: evgesha120190

Найти производную y=tg^2x + ln cosx

Ответы

Автор ответа: natalyabryukhova

Ответ:

$y=tg^2x+ln(cosx)\\y'=2tgx*\frac{1}{cos^2x}+\frac{1}{cosx}*(-sinx)=\frac{2tgx}{cos^2x}-tgx$

Пошаговое объяснение:

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