Question

сократить дробь (x^8+x^6+x^4+x^2+1)/(x^4+x^3+x^2+x+1)

Answer 1

$\frac{8x + 6x + 4x + 2x + 1}{4x + 3x + 2x + x + 1} = \frac{20x + 1}{10x + 1}$