Question

c1=4-3i c2=12+2i дробь c1%c2​

Answer 1

Пошаговое объяснение:

$c_1 = 4-3i; c_2 = 12+2i;\\ \frac{4-3i}{12+2i} = \frac{(4-3i)(12-2i)}{144+4} = \frac{48-44i-6}{148} = \\ = \frac{42}{148} - \frac{44}{148}i = \frac{21}{74} - \frac{11}{37}i;$