Question

8ху(-2х²у⁵)²=решите​

Answer 1

$8xy(-2x^2y^5)^2=8xy*(-2)^2*(x^2)^2(y^5)^2=8xy*4x^{2*2}y^{5*2}=\\\\=32xy*4x^4y^{10}=32x^{1+4}y^{1+10}=32x^5y^{11}$