Question

Решите уравнение (2*x^2-5* x+2)*(2*x^2+7*x+2)=-20*x^2

Answer 1

(2x²-5x+2)×(2x²+7x+2)=-20x²

4x⁴+14x³+4x²-10x³-35x²-10x+4x²+14x+4=-20x²

4x⁴+4x³-27x²+4x+4=-20x²

4x⁴+4x³-27x²+4x+4+20x²=0

4x⁴+2x³+2x³-7x²-4x+8x+4=0

(2x+1)×(2x³+x²-4x+4)=0

(2x+1)×(x+2)+(2x²-3x+2)=0

2x+1=0

x+2=0

2x²-3x+2=0

$x1=-2$

$x2 = - \frac{1}{2}$