Question

Найти алгебраическую форму числа;
(3-4i)^2/(4 - i)

Answer 1

                                           Решение:

(3-4i)^2=9-24i-16=-7-24i
(-7-24i)/(4-i)
Z=((a*c+b*d)+i(bc-ad))/(c^2+d^2)
a=-7 b=-24
c=4 d=-1
ac=-28 bd=24
bc=-96 ad=7
Z=((-28+24)+i(-96-7))/(16+1)=(-4-103i)/17.