Question

решите уравнения
x^{2} =36
x^{2}=1\4
x^{2}+1=3
3-x^{2}=3
2x^{2}+6=0
(х-1\9)^{2}=4\81

Answer 1

$x^2=36\; \; \; \to \; \; x_1=-6\; ,\; x_2=6\\\\x^2=\frac{1}{4}\; \; \; \to \; \; x_1=-\frac{1}{2}\; \; ,\; x_2=\frac{1}{2}\\\\x^2+1=3\; \; \to \; \; x^2=2\; \; ,\; \; x_1=-\sqrt2\; ,\; x_2=\sqrt2\\\\3-x^2=3\; \; \to \; \; x^2=0\; ,\; \; x=0\\\\2x^2+6=0\; \; \to \; \; x^2=-3<0\; ,\; \; x\in \varnothing \\\\(x-\frac{1}{9})^2=\frac{4}{81}\; \; \to \; \; x-\frac{1}{9}=\pm \frac{2}{9}\; \; ,\; x_1=-\frac{2}{9}+\frac{1}{9}=-\frac{1}{9}\; ,\; x_2=\frac{2}{9}+\frac{1}{9}=\frac{1}{3}$