Question

Решете номер 2) а); б)

Answer 1

$-8\, x^{12}\, b^6=(-2)^3\cdot (x^4)^3\cdot (b^2)^3=\Big (-2\, x^4\, b^2\Big )^3\\\\\\-8\, x^{12}\, b^6=(-\sqrt8)^2\cdot (x^6)^2\cdot (b^3)^2=\Big (-2\sqrt2\, x^6\, b^3\Big )^2\\\\\\\\\frac{1}{64}\, x^{36}y^{96}=\frac{1}{4^3}\, (x^{18})^2\, (y^{48})^2=\Big (\frac{1}{4}\cdot x^{18}\cdot y^{48} \Big )^2\\\\\\\frac{1}{64}\, x^{36}y^{96}=\frac{1}{8^2}\, (x^{12})^3\, (y^{32})^3=\Big (\frac{1}{8}\cdot x^{12}\cdot y^{32} \Big )^3$