Question

Прошу, помогите решить!

Answer 1

$frac{64b^2+128b+64}{b} : (frac{4}{b}+4)=\ frac{64(b^2+2b+1)}{b}:(frac{4+4b}{b})=\ frac{64(b+1)^2}{b}*frac{b}{ 4(1+b)}=\ 16b+16 = 16*-frac{15}{16}+16 = -15+16=1$

Answer 2

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