Question

Решите систему неравенств:
/
l 2x-8 ≤0
/
\ 3x+12>0
l
\
Зарание спасибо =)

Answer 1

$\left \{ {{2x-8\leq0 } \atop {3x+12>0}} \right.\\\\\left \{ {{2x\leq8 } \atop {3x>-12}} \right.\\\\\left \{ {{x\leq4 } \atop {x>-4}} \right.\\\\Otvet:\boxed{x\in(-4;4]}$