Question

Помогите Решить (х-7)²=(5-х)²

Answer 1

$(x-7)^2=(5-x)^2\\\\(x-7)^2-(5-x)^2=0\qquad \Big [\; A^2-B^2=(A-B)(A+B)\; \Big ]\\\\\Big ((x-7)-(5-x)\Big )\cdot \Big ((x-7)+(5-x)\Big )=0\\\\(2x-12)\cdot (-2)=0\\\\2x-12=0\\\\x=6$